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Linear charge density 4.00×10−12 c/m surrounds an infinitely long line charge Where m is the mass and v is the initial.an infinitely long line of charge has linear charge density 4.00×10−12c/m. A positively charged elementary particle (mass 1.67×10−27 kg, charge +1.60×10−19 c) is 15.0 cm from this line charge.
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A proton (mass 1.67×10−27 kg,charge +1.60×10−19 c) is 12.0 cm from the line and moving directly toward the line at 4.10×103 m/s There are 4 steps to solve this one A)calculate the proton's initial kinetic energy
Express your answer with the appropriate units
B)how close does the proton get to the line of charge? An infinitely long line of charge creates an electric field that decreases with distance from the line The electric field (e) at a distance (r) from the line is given by e = λ/ (2πε₀r), where λ is the linear charge density and ε₀ is the permittivity of free space. The distance d can be determined using the formula d = kλq/mv^2, where m is the mass of the proton and v is its velocity
The discussion revolves around calculating the closest distance a proton can get to an infinite line of charge with a linear charge density of 8.00×10−12 c/m. An infinitely long line of charge has a linear charge density of 6.00 x 10^ 12 c/m A proton (mass = 7.02 x 10^ 21 kg) is located 15.0 cm from the line and moving directly towards the line at a speed of 2.90 m/s. An infinitely long line of charge has a linear charge density of 8.00×10^−12c/m.a proton is at distance 19.0cm from the line and is moving directly toward the line
The proton, which starts 18.0 cm from the charged line and moves towards it, gets as close as approximately 16.57 cm due to the electric field produced by the linear charge density.
An infinitely long line of charge has linear charge density 6.00×10−12 c/m A proton (mass 1.67×10−27 kg, charge +1.60×10−19 c) is 18.0 cm from the line and moving directly toward the line at 3.20×103 m/s.
